49r^2+3=67

Solution for 49r^2+3=67 equation:

49r^2+3=67

We move all terms to the left:

49r^2+3-(67)=0

We add all the numbers together, and all the variables

49r^2-64=0

a = 49; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·49·(-64)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-112}{2*49}=\frac{-112}{98}
=-1+1/7
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+112}{2*49}=\frac{112}{98}
=1+1/7
$